
| Chatbox |
| SatoruGojo |
| Well- If you use elimination, then to eliminate the x, you just add the first equation -5x-y=8, to the second equation, 5x-3y=16, this can be done because the coefficients of x are opposites -5 and 5 so they cancel out. That gets you with -4y=24 meaning y=-6. Then, to get x, you just plug those variables in. I used the second equation. So it'd be 5x-3(-6)=16. So 5x+18=16. Subtract 18 from sixteen, get -2. -2 divided by 5 is -2/5ths. OvO |
| Eye of Eternity |
| hunters all i know is take off the same things on either side but i dont think that applies here |
| Quests |
| Alliance Battles |
| Challenges |
![]() | Coyote : -2 |
![]() | Polar Bear : +2 |
![]() | Jackal : +4 |
| Chatbox |
| SatoruGojo |
| Well- If you use elimination, then to eliminate the x, you just add the first equation -5x-y=8, to the second equation, 5x-3y=16, this can be done because the coefficients of x are opposites -5 and 5 so they cancel out. That gets you with -4y=24 meaning y=-6. Then, to get x, you just plug those variables in. I used the second equation. So it'd be 5x-3(-6)=16. So 5x+18=16. Subtract 18 from sixteen, get -2. -2 divided by 5 is -2/5ths. OvO |
| Eye of Eternity |
| hunters all i know is take off the same things on either side but i dont think that applies here |
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